12
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there are 10 integers
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
None. But there are three integers there.
The two largest integers when multiplied together is 48 are 6 and 8. To get the single highest integer when multiplying it would be 1 and 48.
333 integers.
48
There are 48.
To find the positive integers less than 2009 that are divisible by 28 but not by 12, we need to find the multiples of 28 that are not multiples of 12. The least common multiple of 28 and 12 is 84, so we need to find multiples of 28 that are not multiples of 84. Since 28 = 2^2 * 7 and 84 = 2^2 * 3 * 7, the multiples of 28 that are not multiples of 84 are those that have an odd power of 2. The highest multiple of 28 less than 2009 that satisfies this condition is 1976. Therefore, there are 1976 / 28 = 71 positive integers less than 2009 that are divisible by 28 but not by 12.
48
9000 integers.
there are 10 integers
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
There are 30 such integers.
There are 9 integers.
None. But there are three integers there.
There are 22 integers between them.
There are 11 integers between -4 and 8.