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Q: How many integers must be negative for the product of three integers to be negative?

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Three of them.

There are 21.

The answer depends on how many negative integers you divide by.

It is positive. Any product of an even number of negative numbers will be positive, regardless of how many positive numbers you have. Similarly any product of an odd number of negative numbers will be negative, regardless of how many positive numbers you have.

None. But there are three integers there.

31.how do you solve?

Five of them.

5

assume that whatever integers you are using are the variables in this. If you haven't been given integers, assume (for the sake of simplicity) that they are one. a * b * c * d * e * f = x -a * b * c * d * e * f = -x -a * -b * c * d * e * f = x -a * -b * -c * d * e * f = -x see a pattern? any ODD number of negative integers will lead to a negative answer, therefore with the limit being 6, the answer will be 5.

There are 11 integers between -4 and 8.

an infinite number. integers are all whole numbers, negative numbers and positive numbers.

750

No- not exactly. Negative integers are not counting numbers. Positive integers are identified with counting numbers. Many authors like to start with zero as a counting number.

Infinitely many in both cases.

There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.

17

10 of them.

-23

There are infinitely many possible answers. -2/3 and 9/10 is one possible answer.

There are 25 of them.

There are 9.

Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.

3 integers: 1200,1500,1800

The product would be a negative number. When you multiply with a negative, it doesn't matter how many negatives, the product will always be a negative. For example: if you were to multiply 2x3x4x5x6x7x8x9x-3x-7x-9=-68,584,320. If you don't believe me, use your calculator.

( -2,0,2 ) three