One or three.
Three of them.
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
750
There are infinitely many possible answers. -2/3 and 9/10 is one possible answer.
17
Three of them.
The answer depends on how many negative integers you divide by.
It is positive. Any product of an even number of negative numbers will be positive, regardless of how many positive numbers you have. Similarly any product of an odd number of negative numbers will be negative, regardless of how many positive numbers you have.
assume that whatever integers you are using are the variables in this. If you haven't been given integers, assume (for the sake of simplicity) that they are one. a * b * c * d * e * f = x -a * b * c * d * e * f = -x -a * -b * c * d * e * f = x -a * -b * -c * d * e * f = -x see a pattern? any ODD number of negative integers will lead to a negative answer, therefore with the limit being 6, the answer will be 5.
31.how do you solve?
None. But there are three integers there.
an infinite number. integers are all whole numbers, negative numbers and positive numbers.
There are 11 integers between -4 and 8.
Five of them.
5
750
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.