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Well, if the tens digit is 1, you have 1 option for the ones digit; if the tens digit is 2, you have two options for the ones digit, if the tens digit is 3, you have 3 options for the ones digit, etc.; up to: if the tens digit is 9, you have 9 options for the ones digit. Add all that up (1 + 2 + 3 + ... + 9).

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Q: How many two digit numbers are there in which the tens digit is greater then the ones digit?

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There are 45 of them.

-3

4

It is 9 times greater.

91

23

How about: 11, 13, 17, 19 .... etc

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 (10,20,21 etc etc)

Is it only 890 and 891

16

8 of them.

Since cents are only in whole numbers, you look at the digit directly to the right of the ones digit. In this case, it is a 7. Since that is 5 or greater, the ones digit is rounded up. The answer is 16 cents.

igk

Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.

It is 0.45

Prime numbers greater than 10 will only end in 1, 3, 7 or 9.

13

9 show the numbers

9218 9425

The answer is in your question, 10,000.

452, 894. None other that I can think of

It can be one of six numbers: 724, 643, 562, 427, 346, 265

It can be 1, 3, 7 or 9. For example, 41, 53, 67 or 79

9

There are 800 such numbers.