I am not sure how it was originally obtained. In some math book I saw how a specific triangular prism could be divided into three congruent pyramids.
The formulat for the volume of a pyramid, or of a cone for that matter, can be obtained quite easily with calculus. The basic idea is to divide the pyramid into thin slices, and calculate the area of each (assuming that each slice is a rectangular block). You might do an approximation in Excel. The thinner the individual slices, the more accurate the result. (Calculus uses more advanced methods, to get the result quicker.)
I am not sure how it was originally obtained. In some math book I saw how a specific triangular prism could be divided into three congruent pyramids.
The formulat for the volume of a pyramid, or of a cone for that matter, can be obtained quite easily with calculus. The basic idea is to divide the pyramid into thin slices, and calculate the area of each (assuming that each slice is a rectangular block). You might do an approximation in Excel. The thinner the individual slices, the more accurate the result. (Calculus uses more advanced methods, to get the result quicker.)
I am not sure how it was originally obtained. In some math book I saw how a specific triangular prism could be divided into three congruent pyramids.
The formulat for the volume of a pyramid, or of a cone for that matter, can be obtained quite easily with calculus. The basic idea is to divide the pyramid into thin slices, and calculate the area of each (assuming that each slice is a rectangular block). You might do an approximation in Excel. The thinner the individual slices, the more accurate the result. (Calculus uses more advanced methods, to get the result quicker.)
I am not sure how it was originally obtained. In some math book I saw how a specific triangular prism could be divided into three congruent pyramids.
The formulat for the volume of a pyramid, or of a cone for that matter, can be obtained quite easily with calculus. The basic idea is to divide the pyramid into thin slices, and calculate the area of each (assuming that each slice is a rectangular block). You might do an approximation in Excel. The thinner the individual slices, the more accurate the result. (Calculus uses more advanced methods, to get the result quicker.)
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I am not sure how it was originally obtained. In some math book I saw how a specific triangular prism could be divided into three congruent pyramids.
The formulat for the volume of a pyramid, or of a cone for that matter, can be obtained quite easily with calculus. The basic idea is to divide the pyramid into thin slices, and calculate the area of each (assuming that each slice is a rectangular block). You might do an approximation in Excel. The thinner the individual slices, the more accurate the result. (Calculus uses more advanced methods, to get the result quicker.)
heron
The formula for finding the volume for a triangular pyramid is half base x height x length. A triangular pyramid has four faces.
formula of the volume of a prism = (base area)(height) formula of the volume of a pyramid = (1/3)(base area)(height) therefore, to convert the volume of a prism to that of a pyramid, just divide it by 3
The answer depends on the what characteristic of the pyramid you want the formula for: its surface area, its volume or something else.
Volume of a pyramid in cubic units: 1/3*base area*height