Just by solving them. Right from first y = (3x - 16)/5
Plug this in the second and you get x * (3x - 16)/5 = 7
Rearranging 3x^2 - 16x - 35 = 0
Could be rewritten as 3 x^2 - 21 x + 5 x - 35 = 0
==> 3x ( x - 7) + 5 (x - 7) = 0
OR (3x+5) (x - 7) = 0
So x = -5/3 or x = 7
Plugging in xy = 7, we can have y = - 21/5 for x = -5/3
And y = 1 gives x = 7
Thus line meets the curve at two points (7,1) and (-5/3 , -21/5)
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
The points of intersection. The coordinates of such points will be the solutions to the simultaneous equations representing the curves.
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
The points of intersection are normally the solutions of the equations for x and y
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
The points of intersection. The coordinates of such points will be the solutions to the simultaneous equations representing the curves.
The points of intersection are: (7/3, 1/3) and (3, 1)
Points of intersection work out as: (3, 4) and (-1, -2)
6 maximum points of intersection
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
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