One inch on the model represents 72 inches -- or six feet -- on the real McCoy. Since the miniature is two inches long, the actual airplane it represents is 12 feet long.
To find the wingspan of Raul's scale model, divide the actual wingspan of 44 feet by the scale factor of 116116. Calculating this gives approximately 0.000379 feet, which is about 0.00455 inches, a very small model size.
To find the length of the scale model, we can set up a proportion based on the original plane's dimensions. The original plane is 150 feet long, and the scale model uses 4 inches for every 50 feet. First, convert 150 feet to inches (150 feet = 1,800 inches). Then, calculate the scale factor: ( \frac{4 \text{ inches}}{50 \text{ feet}} = \frac{4 \text{ inches}}{600 \text{ inches}} = \frac{1}{150} ). Thus, the scale model is 12 inches long (1 foot) since ( 1,800 \text{ inches} \times \frac{1}{150} = 12 \text{ inches} ).
In order to answer this, you first need to convert the feet measurement into inches. This is so that the question has consistent units. There are 12 inches in a foot, so to convert from feet to inches you multiply by 12. In this case we have 6 feet so 6x12 = 72inches. To find the scale, we put the model size as the left number and the represented size as the right number: 1.5:72 This can then be simplified by dividing both numbers by 1.5. This gives the scale of the model as 1:48.
It is: 11*12 = 132 feet
The answer will depend on the size of the real object. Every 4000 inches (333.33.. feet) of the real object will be 1 inch in the model.
33 inches
To find the wingspan of Raul's scale model, divide the actual wingspan of 44 feet by the scale factor of 116116. Calculating this gives approximately 0.000379 feet, which is about 0.00455 inches, a very small model size.
What is the ratio of 555 feet as to 9.25 inches. 6,660 inches : 9.25 = 720 : 1 The model is 720 as to 1 scale, or 1/720th scale model
To find the length of the scale model, we can set up a proportion based on the original plane's dimensions. The original plane is 150 feet long, and the scale model uses 4 inches for every 50 feet. First, convert 150 feet to inches (150 feet = 1,800 inches). Then, calculate the scale factor: ( \frac{4 \text{ inches}}{50 \text{ feet}} = \frac{4 \text{ inches}}{600 \text{ inches}} = \frac{1}{150} ). Thus, the scale model is 12 inches long (1 foot) since ( 1,800 \text{ inches} \times \frac{1}{150} = 12 \text{ inches} ).
12 inches
To find the scale factor, divide the height of the basketball player by the height of the model. The player is 6 feet 8 inches tall, which is equivalent to 80 inches (6 feet x 12 inches/foot + 8 inches). The model is 5 inches tall, so the scale factor is 80 inches / 5 inches = 16. Therefore, the scale factor is 16:1.
In HO scale, which has a ratio of 1:87, 318 feet would be approximately 3.67 feet in model form. To calculate this, you divide 318 by 87, resulting in roughly 3.65 feet or about 43.8 inches. This means that a model representing 318 feet in real life would be about 3 feet and 8 inches long in HO scale.
Fg
In order to answer this, you first need to convert the feet measurement into inches. This is so that the question has consistent units. There are 12 inches in a foot, so to convert from feet to inches you multiply by 12. In this case we have 6 feet so 6x12 = 72inches. To find the scale, we put the model size as the left number and the represented size as the right number: 1.5:72 This can then be simplified by dividing both numbers by 1.5. This gives the scale of the model as 1:48.
It is: 11*12 = 132 feet
The answer will depend on the size of the real object. Every 4000 inches (333.33.. feet) of the real object will be 1 inch in the model.
To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows: [ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ] Thus, the actual length of the train is 450 feet.