The browser used for posting questions on this site is rubbish. It is quite useless for mathematics since it strips out most symbols so that we cannot tell what the question is meant to be.
If f(x) = (pi - x)*sec2x
then f'(x) = (pi - x)*2*sec2x*tan(x) - sec2x
Then, if it is f'(pi/4) that you require, the answer is 3*pi/4 - 1/2.
d/dx(1+tanx)=0+sec2x=sec2x
Is a trigonometric equation which has infinitely many real solutions.
f(x)=9x2(sin x * tan x)f'(x)= 18x(sin x * tan x) + 9x2(cos x * tan x + sec2x * sin x)there might be some identities that allow that to be simplified to look prettier
fx=5x1 / 9
if x is compact, you are simply multiplying the compact number, therefore, 'fx' will also be compact.
d/dx(1+tanx)=0+sec2x=sec2x
It is sec2x, this is the same as 1/cos2x.
Sec(2x) = 1/Cos(2x)
pix-off
By using the chain rule: dy/dx = dy/du x du/dx With y = tan2x Let u = tan x Then: y = u2 du/dx = d/dx tan x = sec2x dy/dx = dy/du x du/dx = 2u sec2x = 2 tan x sec2x
Is a trigonometric equation which has infinitely many real solutions.
Noel Pix was born in 1972.
Mary Pix died in 1709.
Mary Pix was born in 1666.
SET PIX was created in 2006.
Pac-Pix happened in 2005.
The cast of Peter Pix - 2014 includes: Ernesto Piga Carbone as Peter Pix