0
Add your answer:
Earn +20 pts
What is sin squared x equal to?
sin x times sin x. or 1/cosec2(x) or 1 - cos2(x) or tan2(x)*cos2(x) etc, etc.
Differentiate sin x with respect to x?
cos x
How do you differentiate x sinx with respect to x?
You should apply the chain rule d/dx(x.sin x) = x * d/dx(sin x) + sin x * d/dx(x) = x * cos x + sin x * 1 = x.cos x + sin x
What is the Derivative chain rule of (4-x)^3?
The chain rule states that the derivative of f(g(x)) is f'(g(x))⋅g'(x). In other words, it helps us differentiate *composite functions*. For example, sin(x²) is a composite function because it can be constructed as f(g(x)) for f(x)=sin(x) and g(x)=x².
How do you differentiate a cosine function That is what is the derivative of the cosine of x with respect to the independent variable x?
f(x) = Cos(x) f'(x) = -Sin(x) Conversely f(x) = Sin(x) f'(x) = Cos(x) NB Note the change of signs.
How do you simplify tan2 x-1 over 1-sec2 x?
tan2 x + 1 = sec2 x ⇒ 1 - sec2 x = -tan2 x ⇒ (tan2 x - 1) / (1 - sec2 x) = (tan2 x - 1) / -tan2 x = (tan2 x) / (-tan2 x) - 1 / (-tan2 x) = -1 + cot2 x = cot2 x - 1 If you cannot remember tan2 x + 1 = sec2 x, remember and start from: sin2 x + cos2 x = 1 (which is used often) and divide each side by cos2 x: (sin2 x + cos2 x) / cos2 x = 1 / cos2 x ⇒ sin2 x / cos2 x + cos2 x / cos2 x = 1 / cos2 x But sin x / cos x = tan x; and 1/cos x = sec x ⇒ tan2 x + 1 = sec2 x Also, cot x = 1/tan x
Simplify Secant squared of x minus one?
There is a trigonometric identity that states that sec2(x) - tan2(x) = 1, for every x. By rearranging this formula we can find that sec2(x) - 1 = tan2(x).
How do you get a value of 3 using all 6 trigonometric functions?
Sin2(x) + Cos2(x) + Cosec2(x) - Cot2(x) + Sec2(x) - Tan2(x) = 3
What is sin squared x equal to?
sin x times sin x. or 1/cosec2(x) or 1 - cos2(x) or tan2(x)*cos2(x) etc, etc.
What is the derivative of tangent squared?
f(x)= tan2(x) f'(x)= 2tan(x)*sec2(x)
Can someone verify that sec4 theta-sec2 theta equals tan4 theta plus tan2 theta?
sec4(Θ) - sec2(Θ) = tan4(Θ) + tan2(Θ)Factor each side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) [tan2(Θ) + 1]Use the identitiy: 1 + tan2(Θ) = sec2(Θ)We can also write it as: tan2(Θ) = sec2(Θ) - 1Substitute the first form of the identity in the right side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) sec2(Θ)Substitute the second form of the identity in the left side: sec2(Θ) tan2(Θ) = tan2(Θ) sec2(Θ)Is that close enough for you ?Is it worth a trust point ?
Sec²x - tan²x equals?
sec2(x) - tan2(x)= 1/cos2(x) - sin2(x)/cos2(x)= (1 - sin2(x)) / cos2(x)= cos2(x) / cos2(x)= 1
Differentiate sin x with respect to x?
cos x
Differentiate tan3 x?
3 sec23x
How do you differentiate Tanx?
sec^2(x)
Differentiate cos x with respect to x?
d/dx(cos x) = -sinx
How do you differentiate a fraction with x as a numerator?
Suppose you wish to differentiate x/f(x) where f(x) is a differentiable function of x, and writing f for f(x) and f'(x) for the derivative of f(x), d/dx (x/f) = [f - x*f']/(f2)
