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Dwight Jacobi

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8y ago

If y varies directly with x squared and if y = -9 when x = -1 then k = -9

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Q: If y varies directly x squared find k when y -9 and x-1?
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What formula would you use to find the distance from one point to another?

The Distance Formula! D = square root of (y2-y1) quantity squared + (x2-x1) quantity squared


Does distance have a formula?

Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared


How do you find linear equations with just coordinates?

if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)


How do you use a variance-covariance matrix to obtain least squares estimates?

Suppose that you have simple two variable model: Y=b0+b1X1+e The least squares estimator for the slope coefficient, b1 can be obtained with b1=cov(X1,Y)/var(X1) the intercept term can be calculated from the means of X1 and Y b0=mean(Y)-b1*mean(X1) In a larger model, Y=b0+b1X1+b2X2+e the estimator for b1 can be found with b1=(cov(X1,Y)var(X2)-cov(X2,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) to find b2, simply swap the X1 and X2 terms in the above to get b2=(cov(X2,Y)var(X1)-cov(X1,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) Find the intercept with b0=mean(Y)-b1*mean(X1)-b2*mean(X2) Beyond two regressors, it just gets ugly.


How would you find the distance of two points if the line segment that connects them were vertical?

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How do you find the distance between two coordinates in geometry?

square root(x2-x1)squared+(y2-y1)squared


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What formula would you use to find the distance from one point to another?

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Does distance have a formula?

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A set of numbers will have a mean, which is defined as the sum of all the values divided by the number of values. Suppose this mean is m. For each of the values, the squared deviation is the square of the difference between that value and m. Algebraicly, if you have a set {x1, x2, x3, ... , xn}, whose mean is m, then the squared deviation from the mean for x1 is (x1 - m)2.


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What is the difference between Regula-falsi method and secant method?

Regula-Falsi Method evaluates using assumed variables like "a", "b", f(a), f(b) Secant Method Directly works with x1, x2, f(x1), f(x2) Difference is in the Assignment pattern only, otherwise both are used to find root of Non-Linear equations using the same procedure which is: x1= [a * f(b) - b * f(a)]/[f(b)-f(a)] x1= [x0 * f(x1) - x1 * f(x0)]/[f(x1)-f(x0)] Thank You :-)


How do you find linear equations with just coordinates?

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Not quite sure of the given coordinates but in general the distance formula is:- Square root of [(x1-x2)squared+(y1-y2)squared]