33, 35, 37 and 39.
The numbers are 35, 37 and 39.
39
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37, 38 and 39.
The integers are 39 and 40.
117/3 = 39, so the three consective odd integers whose sum is 117 are 37, 39, and 41.
The numbers are 39, 41 and 43.
33, 35, 37 and 39.
The numbers are 35, 37 and 39.
By the uniqueness of integers, the only integer for 39 is 39 itself. And that cannot have a sum of 3.
117
The consecutive odd integers for 114 are 37, 38 and 39.
39
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37 and 39.
Find three consecutive positive even integers whose sum is 123 , Answer