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Is this relation a function (0 0) (1 0) (2 0) (3 0) (4 0)?
Yes, this relation is a function because each input (the first element in each pair) is associated with exactly one output (the second element in each pair). In this case, all inputs 0, 1, 2, 3, and 4 map to the single output 0, which satisfies the definition of a function. Therefore, it meets the criteria necessary to be classified as a function.
Which point lies on the graph of f(x) -2(x 3) 5?
It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
What is the value of the function when the input equals zero?
To determine the value of a function when the input equals zero, you need to evaluate the function at that specific point by substituting zero into the function's equation. For example, if the function is defined as ( f(x) = 2x + 3 ), then ( f(0) = 2(0) + 3 = 3 ). The output will vary depending on the specific function being used.
How do we arrive at the coordinates for y x cubed?
To arrive at the coordinates for the function (y = x^3), you can choose various values for (x) and calculate the corresponding (y) values by cubing each (x). For example, if (x = -2), then (y = (-2)^3 = -8); if (x = 0), then (y = 0^3 = 0); and if (x = 2), then (y = 2^3 = 8). Plotting these pairs ((-2, -8)), ((0, 0)), and ((2, 8)) will give you points on the graph of the cubic function. You can repeat this process with more (x) values to get a more comprehensive set of coordinates.
What is the range of these list of ordered pairs (-3 -1) (0 -2) (4 3) (1 5)?
What is the range of function of y= 9x
What is9 - 2 3 over 7?
5.71
What is9 to the power of 3?
93 = 729
Is this relation a function{(0, 0), (1, 0), (2, 0), (3, 0), (4, 0)}?
yes
What is the function for this function table x -3 -2 0 1 2 y 9 4 0 1 4?
Y = x2
Is the relation (1 3) (4 0) (3 1) (0 4) (2 3) a function?
If those are the only values, no.
What is the domain of this relation (-3 0) (-2 -5) (-2 6) (3 7) (0 -17)?
The domain is the set {-3, -2, 0, 3}. Note that because -2 is mapped to -5 as well as 6, this relationship is not a function.
Which of the ordered pairs below could NOT be in this function{(0, 0), (1, 1), (2, 2), (4, 3)}?
(2, 4)
Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?
No, it is not a function.
What is a rational function graph?
The Equation of a Rational Function has the Form,... f(x) = g(x)/h(x) where h(x) is not equal to zero. We will use a given Rational Function as an Example to graph showing the Vertical and Horizontal Asymptotes, and also the Hole in the Graph of that Function, if they exist. Let the Rational Function be,... f(x) = (x-2)/(x² - 5x + 6). f(x) = (x-2)/[(x-2)(x-3)]. Now if the Denominator (x-2)(x-3) = 0, then the Rational function will be Undefined, that is, the case of Division by Zero (0). So, in the Rational Function f(x) = (x-2)/[(x-2)(x-3)], we see that at x=2 or x=3, the Denominator is equal to Zero (0). But at x=3, we notice that the Numerator is equal to ( 1 ), that is, f(3) = 1/0, hence a Vertical Asymptote at x = 3. But at x=2, we have f(2) = 0/0, 'meaningless'. There is a Hole in the Graph at x = 2.
What percent of 30 is9?
10% of 30 is 3 9 = 3 x 3 So 3 x 10% = answer 30%
How do you Find the equation of a quadratic function with solutions of -2 and ¾?
If: x = -2 and x = 3/4 Then: (4x-3)(x+2) = 0 So: 4x2+5x-6 = 0
Which point lies on the graph of f(x) -2(x 3) 5?
It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
