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Find the value of 2 numbers if their sum is 12 and their difference is 4?
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4
What is the soultion of y -8 and y -2x-12?
If you mean: y = -8 and y = -2x-12 then the solution is x = -2 and y = -8
Three times one number minus a second is eight and the sum of the numbers is twelve?
3x-y=8 x+y=12 3x(12-x)=8 3x-12+x=8 4x-12=8 4x=20 x=5 x+y=12 5+y=12 y=7
-x+ 4 y>-8 x+y8 y?
-x+ 4y>-8, x+y≤3 y≤3-x -x+4(3-x)>-8 -x+12-4x>-8 12-5x>-8 -5x>-20 x>4 y≤3-(4) y≤-1
If y varies directly with x find the constant of variation if x equals 8 and y equals 12?
y = cx when x = 8, y = 12 so that 12 = 8c which gives c = 12/8 = 1.5
Is x plus y a monomial?
no. x is one term, and y is another term, so x+y has two terms, meaning it is a binomial
What is the degree monomial of -5x10y3?
The degree of a monomial is the sum of the exponents of its variables. In the monomial (-5x^{10}y^{3}), the exponent of (x) is 10 and the exponent of (y) is 3. Adding these together gives (10 + 3 = 13). Therefore, the degree of the monomial (-5x^{10}y^{3}) is 13.
What is x y 12 and x - y 4 using the addition method?
16
What is an example of a monomial?
A monomial is an algebraic expression with only one term. One example of a monomial is 4x. Other examples are 4x^2 or 8/y
Evaluate the following expression if x equals 12 y equals 8 and z equals 6?
x=y-8 z=x+12
What are the steps in finding the common monomial factor?
It is similar to finding the greatest common factor only you may have variables involved, so you may factor a constant and variable(s) which all terms are divisible by, for example: The common monomial factor in the following: 5x^2+5x would be 5x because both terms are divisible by 5 and x. 5x (x+1). Just find the constant and variable all terms are divisible by and then the product of those is your common monomial factor.
What is the factor of monomial of 5xysquared?
The factors of the monomial (5xy^2) include the numerical coefficient and the variable components. Specifically, the factors are (5), (x), (y), and (y) (since (y^2) can be expressed as (y \cdot y)). Thus, the complete factorization is (5 \cdot x \cdot y \cdot y).
