Yes, The quotiant is 8.
NO, lets take an example.. 24 is divided by 2 and 8 both.. but not by 16..
The number 13 is not divisible by 2 or 3 and falls between 12 and 16. It is an odd number, making it not divisible by 2, and the sum of its digits (1 + 3 = 4) is not divisible by 3. Thus, 13 meets the criteria specified.
The number 32 is divisible by 1, 2, 4, 8, 16, and 32.
64 is divisible by 1, 2, 4, 8, 16, 32, 64.
16 is even because it is divisible by 2 and has a 6 in the ones place.
Nope. 16 is divisible by 1, 2, 4, 8, 16.
yes it is because 16 is divisible by 2,4,and 8
NO, lets take an example.. 24 is divided by 2 and 8 both.. but not by 16..
6+8+2= 16, 16 isn't divisible by 3, so no, 682 is not
No. It doesn't end in a 5 or 0.
Not evenly because it will have a remainder of 4
Not evenly. 16 and 18 are.
8, 16, 24, 32... All multiples of 8 are also divisible by 2 and 4.
The digital root (sum of digit) must be divisible by 9, and the number formed by the last 4 digits must be divisible by 16. The second requirement ensures that the number is divisible by 16.
The number 32 is divisible by 1, 2, 4, 8, 16, and 32.
72 and 16 are divisible by 1, 2, 4, 8.
smallestnumber divisible by both 16 and 24 = 48Prime factorization of:16 = 2 * 2 * 2 * 224 = 2 * 2 * 2 .....* 3=============LCM=2* 2 * 2 * 2 * 3 = 48