3 is not divisible by 126. 126 is divisible by 3.
3 is not divisible by 72. 72 is divisible by 3.
512 is not divisible by 3.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
362880
362880 is one possibility.
362880
362880 ways. 9!=9*8*7*6*5*4*3*2*1=362880
362880
Probably 9! to the power 9! to the power 9! which is 362880^362880^362880 Another contributor suggested 9^9^9
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
9 factorial = 9! = (9*8*7*6*5*4*3*2*1) = 362880
1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 = 362880