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Out of that list, 2, 3, 6 and 9.

Yes to all of them.

Yes.

Q: Is 96240 divisible by 2 3 5 10?

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It is divisible by 2, 5 and 10 but not the rest.

Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.

610 is divisible by these factors: 1, 2, 5, 10, 61, 122, 305, 610.

no not by 10 as 216 ends in 6 not 0 same with 5 as does not end in 5 or 0 216 = 2 x 108 = 3 x 72 = 4 x 54 = 6 x 36 = 9 x 24 --------------------------------------- Last digit of 216 is even (one of {0, 2, 4, 6, 8}) so 216 is divisible by 2 6 + 1 + 2 = 9 which is divisible by 3 so 216 is divisible by 3 Last 2 digits are 16 which are divisible by 4, so 216 is divisible by 4 Last digit is not 0 nor 5, so 216 is NOT divisible by 5 216 is divisible by both 2 and 3 so 216 is divisible by 6 6 + 1 + 2 = 9, so 216 is divisible by 9 Last digit is not 0, so 216 is NOT divisible by 10 216 is divisible by 2, 3, 4, 6, 9. 216 is NOT divisible by 5 nor 10.

Out of that list, only 2.

Related questions

First Find the Sum of The Digits 9+6+2+4+0=21 So can 2,3,5, and 10 fit into 21? No so its false 2=False 3=True 5=False 10=False

All Factors of 96240:1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240, 401, 802, 1203, 1604, 2005, 2406, 3208, 4010, 4812, 6015, 6416, 8020, 9624, 12030, 16040, 19248, 24060, 32080, 48120, 96240

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

It is evenly divisible by 2 and 10 but not by 3 and 9.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

It is divisible by 2, 5 and 10, but not 3 and 9.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

It is evenly divisible by 2 and by 3.