The integer is 10.
Yes and no. It depends on your definition of square root. By the actual one, yes. All non-negative numbers have a square root. That square root might be irrational but it has a square root, nonetheless. 10 isn't a square number because there's no integer that can be squared to make ten but 10 definitely has a square root: 3.16227766....... If by square root you mean an integer square root, then no. If a number has an integer as its square root then you could square that integer to get the number, making it a square number.
The square root of an integer is a CYCLOTOMIC integer.
No it is a complex number the number 10i, which has an integer part (10) and an imaginary part (i), where i=square root of -1
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
3.33333...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.