No.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
Yes it is.Since the square of an integer is called a perfect square, then the square root of a perfect square must be an integer.
No, the square root of 24 is NOT an integer. An integer is a whole number, and the square root of 24 is 4.89897948557.
No.
because its square root is 7.071067812. to be a square #, its square root needs to be an integer(or whole #) -Nicci
The square root of an integer is a CYCLOTOMIC integer.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
The square root of 36 is 6 which is an integer.