Th dice have 6 sides and each side have one number from 1-6 so that there are 6 possible outcomes if you rolled the dice
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Assuming this is a standard die then this is simply a list of the numbers
ie 1, 2, 3, 4, 5, 6.
The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.
The probability of getting heads only once when a fair coin is tossed 4 times is 4/16 or 0.25. This is because there are 4 favorable outcomes where heads appears exactly once, out of the 16 possible outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.