Th dice have 6 sides and each side have one number from 1-6 so that there are 6 possible outcomes if you rolled the dice
Assuming this is a standard die then this is simply a list of the numbers
ie 1, 2, 3, 4, 5, 6.
The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
7878
There are eight (8).
The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
7878
48
Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
enless you include it landing on it's side the two possible outcomes for this are: Heads and Tails
To determine the amount of possible outcomes, there must be a number of sections for each spinner
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.