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Th dice have 6 sides and each side have one number from 1-6 so that there are 6 possible outcomes if you rolled the dice
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A coin is tossed If it comes out heads a die is then tossed once if a tail appears the coin is tossed one more time List the possibilities as to how many outcomes are possible?
The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
If a die is tossed once probability of it landing on a 6?
Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.
What is the probability of getting heads only once if a fair coin is tossed 4 times?
The probability of getting heads only once when a fair coin is tossed 4 times is 4/16 or 0.25. This is because there are 4 favorable outcomes where heads appears exactly once, out of the 16 possible outcomes.
How many possible outcomes are there when 4 fair coins are tossed at once?
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
How many possible outcomes would there be if thirty two coins were tossed once?
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
How many possible outcomes would be if three coins were tossed once?
There are eight (8).
A coin is tossed If it comes out heads a die is then tossed once if a tail appears the coin is tossed one more time List the possibilities as to how many outcomes are possible?
The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
If a die is tossed once probability of it landing on a 6?
Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.
What is the probability of getting heads only once if a fair coin is tossed 4 times?
The probability of getting heads only once when a fair coin is tossed 4 times is 4/16 or 0.25. This is because there are 4 favorable outcomes where heads appears exactly once, out of the 16 possible outcomes.
How many possible outcomes are there when 4 fair coins are tossed at once?
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
How many possible outcomes would there be if thirty two coins were tossed once?
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
How many different combinations are possible if a number cube is tossed once and a coin is tossed twice?
7878
How many different combinations are possible if number cube is tossed once and a coin is tossed three times?
48
What is the probability to get tail at least once when 6 coins are tossed simultaneously?
Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%
How many possible outcomes if each coin is flipped once?
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
How many different combinations are possible if a coin is tossed once and a number cube is tossed twice?
There are 72 permutations of two dice and one coin.
How many different combinations are possible if a coin is tossed twice and a number cube is tossed once?
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
