No. Let's assume the plane has coordinates x and y; the vector outside the plane has a component for the z-coordinate. In that case, another vector (or several) must also have a component in the z-coordinate, to compensate.
No. Let's assume the plane has coordinates x and y; the vector outside the plane has a component for the z-coordinate. In that case, another vector (or several) must also have a component in the z-coordinate, to compensate.
No. Let's assume the plane has coordinates x and y; the vector outside the plane has a component for the z-coordinate. In that case, another vector (or several) must also have a component in the z-coordinate, to compensate.
No. Let's assume the plane has coordinates x and y; the vector outside the plane has a component for the z-coordinate. In that case, another vector (or several) must also have a component in the z-coordinate, to compensate.
No. Let's assume the plane has coordinates x and y; the vector outside the plane has a component for the z-coordinate. In that case, another vector (or several) must also have a component in the z-coordinate, to compensate.
Take any three vectors in a plane which, when placed end-to-end form a triangle. The resultant of the three vectors will be zero.
No. For three vectors they must all lie in the same plane. Consider 2 vectors first. For them to resolve to zero, they must be in opposite direction and equal magnitude. So they will lie along the same line. For 3 vectors: take two of them. Any two vectors will lie in the same plane, and their resultant vector will also lie in that plane. Find the resultant of the first two vectors, and the third vector must be along the same line (equal magnitude, opposite direction), in order to result to zero. Since the third vector is along the same line as the resultant vector of the first two, then it must be in the same plane as the resultant of the first two. Therefore it lies in the same plane as the first two.
The orientation of the three vectors that sum to zero must be coplanar, contained in the same common plane, including being contained in a common line in a plane.
Yes, put the three vectors in a plane, with a separation of 120 degrees between each vector and each of the other vectors.
Yes if you put them "head to tail" and the head of the fourth one points to the tail of the first one the resultant is zero.
No. The tenth vector would have to be matched by one equal and opposite vector to yield a zero resultant, or by multiple vectors in the second plain collectively yielding a zero resultant for that plane. It would be possible, for example, for 8 vectors to be on the same plane and two on a different plane to give a zero resultant.
Take any three vectors in a plane which, when placed end-to-end form a triangle. The resultant of the three vectors will be zero.
No. For three vectors they must all lie in the same plane. Consider 2 vectors first. For them to resolve to zero, they must be in opposite direction and equal magnitude. So they will lie along the same line. For 3 vectors: take two of them. Any two vectors will lie in the same plane, and their resultant vector will also lie in that plane. Find the resultant of the first two vectors, and the third vector must be along the same line (equal magnitude, opposite direction), in order to result to zero. Since the third vector is along the same line as the resultant vector of the first two, then it must be in the same plane as the resultant of the first two. Therefore it lies in the same plane as the first two.
The orientation of the three vectors that sum to zero must be coplanar, contained in the same common plane, including being contained in a common line in a plane.
When performing the cross product of two vectors (vector A and vector B), one of the properites of the resultant vector C is that it is perpendicular to both vectors A & B. In two dimensional space, this is not possible, because the resultant vector will be perpendicular to the plane that A & B reside in. Using the (i,j,k) unit vector notation, you could add a 0*k to each vector when doing the cross product, and the resultant vector will have zeros for the i & jcomponents, and only have k components.Two vectors define a plane, and their cross product is always a vector along the normal to that plane, so the three vectors cannot lie in a 2D space which is a plane.
Yes, put the three vectors in a plane, with a separation of 120 degrees between each vector and each of the other vectors.
Yes if you put them "head to tail" and the head of the fourth one points to the tail of the first one the resultant is zero.
Not necessarily. Suppose you have three vectors (ax + by + cz), (gx + hy +iz) and (mx + ny + oz) then as long as a+g+m = b+h+n = c+i+o = 0 the resultant is zero.
yes the resultant of the two vectors can be zero.it can be illustrated by drawing following diagram.a triangle may be considered as a vector diagram in which the force polygon close and the resultant of the three vectors is zero.
Coplanar :The vectors are in the same plane.Non coplanar :The vectors are not in the same plane.
Coplanar vectors are vectors lying in the same plane.
You can use the component method for finding two or more vectors. Use the X and Y axis. Ex. If you have 5 vectors given-Draw a cartesian plane for every vectors-Get the equivalent value of X and Y for Every vectors(use the SOHCAHTOA rules).-Get the summation of X and Y then use Phythagorean Theorem. For finding the Angle, use the Tan theta. Save