Let's denote the two numbers as x and y. We know that xy = 112 and x + y = -12. By solving these two equations simultaneously, we can find the values of x and y. One possible solution is x = -14 and y = -8. These numbers satisfy both conditions: -14 * -8 = 112 and -14 + (-8) = -12.
The two numbers that add to give you 25 and multiply to give you 26 are 24 and 1. When you add 24 and 1, you get 25, and when you multiply them, you get 26.
136
The two numbers that add to 38 and multiply to give 72 are 36 and 2. When you add them together, 36 + 2 equals 38, and when you multiply them, 36 × 2 equals 72.
-82
The two numbers that add to give 1 and multiply to give -4 are 4 and -3. When you add them, 4 + (-3) = 1, and when you multiply them, 4 × (-3) = -12. So, the correct answer is 4 and -3.
130
There are infinitely many possible pairs of numbers. An easy pair to remember is 1 and 112.
The two numbers that add to give you 25 and multiply to give you 26 are 24 and 1. When you add 24 and 1, you get 25, and when you multiply them, you get 26.
136
Either (a) multiply 112 by 0, by 1, by 2, etc., or (b) starting with zero, add 112 repeatedly to get the following numbers in the sequence of multiples.
The numbers are: 20 and -48
736
-82
Well you can multiply 2 and 2 and it will give you 4 when u add
The two numbers that add to give 1 and multiply to give -4 are 4 and -3. When you add them, 4 + (-3) = 1, and when you multiply them, 4 × (-3) = -12. So, the correct answer is 4 and -3.
5 and 6
113