it depends on which 8 numbers your talking about
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
9
There are twelve possible solutions using the rule you stated.
-8
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
it depends on which 8 numbers your talking about
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
There are 5,040 combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
9
There are twelve possible solutions using the rule you stated.
-8