With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
There are 5,040 combinations.
There are 24 combinations using each digit once per combination: 1234 1243 1324 1342 1423 1432 2134 2143 2314 2341 2413 2431 3124 3142 3214 3241 3412 3421 4123 4132 4213 4231 4312 and 4321.
There are 7 digits from 0-6 To determine if a number is divisible by 4, we only need look at the last 2 digits. Possibilities are: [135][26] => 12, 16, 32, 36, 52, 56 and [0246][04] => 04, 20, 24, 40, 60, 64 (ignoring 00 and 44) There are 8 combinations without a 0, and 4 with a 0. Of the 8 combinations without a 0, We can only pick 4 of the remaining digits for the ten thousand digit. This leaves us with 4 digits for the thousands digit, 3 for the hundreds digit Of the 4 combinations with a 0, similarly we have 5 X 4 X 3 possibilities for the rest of the digits. 8 * 4 * 4* 3 + 4 * 5 * 4 * 3 = 32 * 12 + 20 * 12 = 52 * 12 = 624 There are 624 possible numbers.
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
It can be calculated as factorial 44! = 4x3x2x1= 60
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
128
1
There are 5,040 combinations.
9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.
There are 210 4 digit combinations and 5040 different 4 digit codes.
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.