-3, -5, -7, -9, -11
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.
The integers are -1, 1 and 3.
-3, -1, 1, 3, 5
-3, -5, -7, -9, -11
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.
No. For example, 5 is an odd integer and 3 is an odd integer, yet 5/3 is neither an integer nor odd (as odd numbers are, by definition, integers).
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
-6, -5, -4, -3 and -2.
The first odd positive integers are "1" and "3" which the sum is 4.
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
90
189/3 = 63 So the three odd integers are 61, 63 and 65