What are the combinations for 1234567890?

Answer 1

Oh, dude, you're asking about combinations now? That's like asking me to count all the grains of sand on a beach. There are like a bazillion combinations for those numbers, so good luck with that. Just remember, math can be a real party pooper sometimes.

Answer 2

To calculate the number of combinations for the sequence 1234567890, we can use the formula for combinations of n items taken k at a time, which is n! / (k!(n-k)!). In this case, there are 10 items (numbers) and we are taking all 10 at a time, so the number of combinations is 10! / (10!(10-10)!) = 10! / (10! * 0!) = 1. Therefore, there is only 1 combination for the sequence 1234567890.

Answer 3

First position can be any one of 10 numbers.

One number has been taken so the second position can be any one of 9 numbers.

Third position can be any one of 8 numbers.

7,6,5,4,3,2...

Last position can only be 1 number as all the others will have been taken.

Which leaves you with 10x9x8x7x6x5x4x3x2x1 or 10! (factorial).

10! = 3,628,800 combinations.

If numbers can be repeated this makes things easier as you can just multiply by 10 for each position - 10x10x10x10x10x10x10x10x10x10 or 10^10.

10^10 = 10,000,000,000 combinations.

Answer 4

There are over 3.6 billion possible combinations for a 10-digit number like 1234567890. This number can be rearranged in various ways, but each combination would still consist of the same set of digits (1, 2, 3, 4, 5, 6, 7, 8, 9, 0).

Answer 5

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