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First position can be any one of 10 numbers.

One number has been taken so the second position can be any one of 9 numbers.

Third position can be any one of 8 numbers.

7,6,5,4,3,2...

Last position can only be 1 number as all the others will have been taken.

Which leaves you with 10x9x8x7x6x5x4x3x2x1 or 10! (factorial).

10! = 3,628,800 combinations.

If numbers can be repeated this makes things easier as you can just multiply by 10 for each position - 10x10x10x10x10x10x10x10x10x10 or 10^10.

10^10 = 10,000,000,000 combinations.

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13y ago
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6mo ago

There are over 3.6 billion possible combinations for a 10-digit number like 1234567890. This number can be rearranged in various ways, but each combination would still consist of the same set of digits (1, 2, 3, 4, 5, 6, 7, 8, 9, 0).

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Q: What are the combinations for 1234567890?
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