First position can be any one of 10 numbers.
One number has been taken so the second position can be any one of 9 numbers.
Third position can be any one of 8 numbers.
7,6,5,4,3,2...
Last position can only be 1 number as all the others will have been taken.
Which leaves you with 10x9x8x7x6x5x4x3x2x1 or 10! (factorial).
10! = 3,628,800 combinations.
If numbers can be repeated this makes things easier as you can just multiply by 10 for each position - 10x10x10x10x10x10x10x10x10x10 or 10^10.
10^10 = 10,000,000,000 combinations.
To create combos on Spellcaster in "I Am Learning," you can combine different spells and elements to see how they interact and produce different effects. Experiment with mixing various spells and elements to discover new combinations and their outcomes. Keep trying different combinations to see what works best and have fun exploring the possibilities of the game.
Isocost lines are straight because they represent all the possible combinations of inputs that can be purchased for a given total cost. Since the cost per unit of input is constant along a straight line, different combinations on the line will have the same total cost. This allows firms to find the most cost-effective way to produce a given level of output.
Neoassociationism is a modern form of the associationist perspective in psychology, which posits that complex mental processes can be understood as combinations of simple associative elements. It focuses on how different ideas, thoughts, and sensations become associated in the mind through experiences and learning.neoassociationism emphasizes the importance of context and the role of emotional processes in cognition.
Color theory is a set of principles that describe how colors interact with each other. It includes concepts such as the color wheel, color harmony, and the psychological effects of colors. Color theory is used in various fields such as art, design, and marketing to create visually appealing combinations and communicate messages effectively.
The teacher can choose 5 students out of 12 in 792 different ways using combinations. This calculation is based on the formula for combinations: C(n, k) = n! / [k! * (n - k)!], where n is the total number of students (12) and k is the number of students the teacher wants to choose (5).
If repeats are allowed than an infinite number of combinations is possible.
The answer is 10C3 = 10*9*8/(3*2*1) = 120 combinations.
5435 441521 14241553 514152153 457745641 543646313 IDK TO HarD!
1234567890
2469135780
zero
1.52415788 × 1018
1234567890-1234567856 = 34
1 plus 1234567890 is 1234567891
1234567890+9876543210=11,111,111,100
1234567890 + 1098765432 = 2333333322
4000 + 1234567890 = 1234571890