To calculate the number of combinations possible with the numbers 1, 2, 3, and 4, you can use the formula for permutations without repetition, which is n! / (n-r)!. In this case, n is 4 (the total number of numbers) and r is also 4 (since you are using all the numbers). Therefore, the number of combinations is 4! / (4-4)! = 4! / 0! = 4 x 3 x 2 x 1 = 24. So, there are 24 possible combinations you can make with the numbers 1, 2, 3, and 4.
1234
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
1234, 1235 and 1236.
4 of them. In a combination the order of the numbers does not matter.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
1234
Since the order of the digits does not matter there are only five combinations: 1234, 1235, 1245, 1345 and 2345.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
By the uniqueness of numbers, the only number for 1234 is 1234 itself.
32 -(1+4) =27
9999 + 1 * * * * * That is so wrong! There are 10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers from the set of ten 1-digit numbers, 0 1, 2, ... 9 When considering combinations, 1234 is the same as 2314 or 4123 etc. Actually... 4 numbers to be arranged with ten different possibilities each will give a total of 10^4 combinations, or 10,000.
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
1234, 1235 and 1236.