9999 + 1
* * * * *
That is so wrong!
There are 10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers from the set of ten 1-digit numbers, 0 1, 2, ... 9
When considering combinations, 1234 is the same as 2314 or 4123 etc.
Actually...
4 numbers to be arranged with ten different possibilities each will give a total of 10^4 combinations, or 10,000.
56 combinations. :)
There are 7 combinations. Each combination excludes a different one of the seven numbers.
7
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
Just one. unless you count 123456 different from 132456 then there are 46656 * * * * * But you cannot count 123456 as different from 132456 since it is NOT a different combination. And the question was about combinations.
4!=4x3x2x1=24
10
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
all numbers have to be different 720 360 (6*5*4*3*2*1), * * * * * Wrong. Combinations do not have to be different. Those are permutations. There are only 6C4 = 6*5/(2*1) = 15 combinations.
120
56 combinations. :)
How many numbers are there are in each combination ?If one, then 4 combinations.If two, then 6 combinations.If three, then 4 combinations.If four, then only 1 combination.
there are 13,983,816 combinations.
There are 7 combinations. Each combination excludes a different one of the seven numbers.
There are 360 of them.
7
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.