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What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?
Wiki User
∙ 6y ago
If: 3x-y = 5 then y^2 = (3x_5)^2 => 9x^2 -30x+25
If: 2x^2 + y^2 = 129 then y^2 = 129-2x^2
So: 9x^2 -30x+25 = 129-2x^2
Transposing terms: 11x^2 -30x -104 = 0
Factorizing the above: (11x-52)(x+2) = 0 meaning x = 52/11 or x = -2
By substituting x into the original equation intersections are at: (52/11, 101/11) and (-2, -11)
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThey are (-2, -11) and (52/11, 101/11).
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