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If: 3x-y = 5

Then: y^2 = 9x^2 -30x +25

If: 2x^2 +y^2 = 129

Then: 2x^2 +9x^2 -30x +25 = 129

Transposing terms: 11x^2 -30x -104 = 0

Factorizing the above: (11x-52)(x+2) = 0 meaning x = 52/11 or x = -2

Therefore by substitution points of intersection are at: (52/11, 101/11) and (-2, -11)

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6y ago
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6y ago

They are (-2, -11) and (4.7272..., 9.1818...).

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Q: What are the points of intersection when the line 3x -y equals 5 crosses the curve 2x squared plus y squared equals 129?
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