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You cannot "solve" a single linear equation with two variables. Alternatively, you could argue that any one of the infinitely many points on the line represented by that equation is a solution.
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
The equation for 3y + 3y = -1 is 3y + 3y = -1.
this can not be solved un less with another equation
This is an equation of a line. There are an infinite number of solutions which are all points on the line. It is a linear equation.
x=10 y=4
87 = 3yDivide each side of the equation by 3:29 = y
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
You'd need another equation to sub in
This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.