For y - 2y - 3y equals 0, y equals 0.
x+3y=2 x= -5 y = 1
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
If: y-2+3y =10 Then: y+3y = 10+2 And: 4y = 12 Divide both sides by 4 to find the value of y: y = 3
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
For y - 2y - 3y equals 0, y equals 0.
3y=ab. Divide by 3 to get y=ab/3
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
n=3,y=4 2(n+3y)=30
x+3y=2 x= -5 y = 1
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
If: y-2+3y =10 Then: y+3y = 10+2 And: 4y = 12 Divide both sides by 4 to find the value of y: y = 3
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
3y + 8 = 3 -8 -8 3y=-5 (3y)/3=-5/3 y=(-5/3)
Yes and it works out that x = 3 and y = 4
y + 2y = 4 (2+1)y = 4 3y = 4 (3y)/3 = 4/3 y = 4/3 = 1.3333333333333333333