Not all rational equations have a single solution but can have more than one because of having polynomials. All rational equations do have solutions that cannot fulfill the answer.
No. An equation as simple as x2 = 1 has two solutions.
They are the solutions for the reduced quadratic.
No. They can just as well have zero solutions, several solutions, or even infinitely many solutions.
Numbers are numbers, not questions or equations. They do not have solutions.
Irrational numbers can be divided into algebraic numbers and transcendental numbers. Algebraic numbers are those which are the solutions to algebraic equations with integer coefficients: for example, x^2 = 2. Transcendental numbers are those for which there are no corresponding algebraic equations. pi, e are two examples.
It means it is not an algebraic number. Algebraic numbers include square roots, cubic roots, etc., but more generally, algebraic numbers are solutions of polynomial equations.
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
A system of equations has an infinite set of solutions when the equations define the same line, such that for ax + by = c, the values for two equations is a1/a2 + b1/b2 = c1/c2. Equations where a variable drops out completely, e.g. 3x - y = 6x -2y there are either an infinite number of solutions, or no solution at all.
what are the example of quotient orf rational algebraic expression.
The answers to equations are their solutions
Finding the point of intersection using graphs or geometry is the same as finding the algebraic solutions to the corresponding simultaneous equations.