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Equation: 8x^2 -26x +15 =0 I

Divide all terms by 8: x^2 -26/8 +15/8 = 0 and complete the square as follows:-

(x -13/8)^2 -169/64 +15/8 = 0 => (x-13/8)^2 = 49/64

Square root both sides: x-13/8 = -/+ 7/8

Add 13/8 to both sides: x = 13/8 -/+ 7/8

Therefore solutions are: x = 5/2 or x = 3/4

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7y ago
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7y ago

8x^2 - 26x + 15 = 0Divide through by 8: x^2 - 13/4x + 15/8 = 0

13/4 divided by 2 is 13/8 so (x - 13/8)^2 - (13/8)^2 + 15/8 = 0

=> (x - 13/8)^2 = (13/8)^2 - 15/8 = 169/64 - 120/64 = 49/64

taking square roots, x - 13/

therefore x = 13/8 +/- 7/8

=> x = 20/8 or x = 6/8

=> x = 5/2 or x = 3/4.

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Q: What are the solutions to the equation of 8x squared -26x plus 15 equals 0 solved by completing the square?
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