Equation: 8x^2 -26x +15 =0 I
Divide all terms by 8: x^2 -26/8 +15/8 = 0 and complete the square as follows:-
(x -13/8)^2 -169/64 +15/8 = 0 => (x-13/8)^2 = 49/64
Square root both sides: x-13/8 = -/+ 7/8
Add 13/8 to both sides: x = 13/8 -/+ 7/8
Therefore solutions are: x = 5/2 or x = 3/4
8x^2 - 26x + 15 = 0Divide through by 8: x^2 - 13/4x + 15/8 = 0
13/4 divided by 2 is 13/8 so (x - 13/8)^2 - (13/8)^2 + 15/8 = 0
=> (x - 13/8)^2 = (13/8)^2 - 15/8 = 169/64 - 120/64 = 49/64
taking square roots, x - 13/
therefore x = 13/8 +/- 7/8
=> x = 20/8 or x = 6/8
=> x = 5/2 or x = 3/4.
There's an equals missing...
No. It's a quadratic equation, and it has two solutions.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
no
It is a quadratic equation and its solutions are: x = 4 or x = -9
The quadratic equation will have two solutions.
There's an equals missing...
No. It's a quadratic equation, and it has two solutions.
The solutions to the quadratic equation are: x = -1 and x = 6
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9
no
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
It is a quadratic equation and its solutions are: x = 4 or x = -9
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
This quadratic equation has no solutions because the discriminant is less than zero.