-6
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
no
No, it is not.
They are: (3, 1) and (-11/5, -8/5)
That equals 2xy + 3y which factors to y(2x + 3)
yes 3xy=6
x = -1 y = 2 2x3 - 3xy = 2 (-1)3 - 3(-1)(2) = 2 (-1) - (-6) = -2 + 6 = 4 Suggestion: Please be careful around problems like this until you have some more experience.
To evaluate the expression (3xy + 4y^3) when (y = 2) and (x = 5), substitute the values into the expression. This gives: [ 3(5)(2) + 4(2^3) = 30 + 4(8) = 30 + 32 = 62. ] Thus, the value of the expression is 62.
3xy - 3xy = 0
(x + 6y)(x - 3y)
M=3 because y+y+y= 3xY and MY= MxY
Whooop!