-6
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
no
No, it is not.
They are: (3, 1) and (-11/5, -8/5)
That equals 2xy + 3y which factors to y(2x + 3)
yes 3xy=6
x = -1 y = 2 2x3 - 3xy = 2 (-1)3 - 3(-1)(2) = 2 (-1) - (-6) = -2 + 6 = 4 Suggestion: Please be careful around problems like this until you have some more experience.
3xy - 3xy = 0
(x + 6y)(x - 3y)
M=3 because y+y+y= 3xY and MY= MxY
Whooop!
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero