5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
-6n-2n 16 can be solved mathematically getting n = - 2.
Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.
The answer is: n=4.
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
5n + 6n - 2n
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
If: -6n-2n = 16 Then: n = -2
15/6n + 6/6n = 21/6n = 7/2n
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
-6n-2n 16 can be solved mathematically getting n = - 2.
Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.
The answer is: n=4.
First we must collect and simplify 'like terms' 2n-6n-36. 2n-6n = -4n Therefore, -4n-36 Take out the greatest common factor. -4 (n+9) Ans = -4 (n+9)
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
m2 - 4mn - 12n2 = m2 - 6mn + 2mn - 12n2 = m(m - 6n) + 2n(m - 6n) = (m + 2n)(m - 6n)