13
To get 5 using the numbers 19, 2, 6, and 3, you can subtract 6 from 19 to get 13, then subtract 3 from 13 to get 10, and finally subtract 2 from 10 to get 8. So, you cannot get 5 using these specific numbers.
Subtract a negative 1. 19 - (-1) = 20
24/30 - 5/30 = 19/30
19 can go into 127 a total of 6 times, since 19 multiplied by 6 equals 114. When you subtract 114 from 127, you have a remainder of 13. Therefore, 19 goes into 127 six full times with a remainder of 13.
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
If you subtract 19 from 25, you get a result of 6. This is calculated by adding 6 to 19.
To get 5 using the numbers 19, 2, 6, and 3, you can subtract 6 from 19 to get 13, then subtract 3 from 13 to get 10, and finally subtract 2 from 10 to get 8. So, you cannot get 5 using these specific numbers.
19
Subtract a negative 1. 19 - (-1) = 20
24/30 - 5/30 = 19/30
19 can go into 127 a total of 6 times, since 19 multiplied by 6 equals 114. When you subtract 114 from 127, you have a remainder of 13. Therefore, 19 goes into 127 six full times with a remainder of 13.
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
-1328
When you subtract 19 ones from 19 tens, you are essentially calculating 190 (the value of 19 tens) minus 19 (the value of 19 ones). This results in 171. Therefore, the difference is 171.
To solve the equation ( 11 + 8q = 3q - 19 ), first, isolate the variable ( q ). Subtract ( 3q ) from both sides to get ( 11 + 5q = -19 ). Then, subtract 11 from both sides, resulting in ( 5q = -30 ). Finally, divide by 5 to find ( q = -6 ).
15
5h + 6 = 25 Subtract 6 from both sides: 5h = 19 Divide both sides by 5: h = 3.8 h = 3.8