I will assume that we are taking d/dx, not d/dn. There are two ways to interpret what you asked. First way is (sinx)^(2n). Second way is sin(x^(2n)). First answer: 2n(sinx)^(2n-1)(cosx)=2ncosx(sinx)^(2n-1). Second answer: cos(x^(2n))(2nx^(2n-1)).
When n=53, then 2n + 1 = 107
It is a statement that is equivalent to the equation:(2n+1)*(2n+3) = (2n+1)+(2n+3) + 23.
A Mersenne prime has the form 2n-1. For 2n-1 to be prime, n must also be prime. Perfect numbers have the form 2n-1(2n-1) where 2n-1 is a Mersenne prime, so when a new Mersenne prime is discovered, another perfect number is also found.
5-2n=3 -2n=3-5 -2n=-2 n=1
Any even number can be written in the form 2n for some natural number n.Any odd number can be written as 2n+1 for a natural number nNow add an even to an odd.2n+2n+1=4n+1 which is 2(2n)+1 and this is the form for an odd number.
(2n)2 + (2n+1)2 = 4n2 + 4n2 + 2n + 2n + 1 = 8n2 + 8n + 1 = 8(n2 + n) + 1 Anything multiplied by 8 will be even. Add 1 makes it odd. Mark Ravenwood Folkestone School for Girls
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n
2N is 2 normal; add 56,11 mL sulfuric acid 98 % to 250 mL deionized water. Mix and add water up to 1 000 mL.
2n - 7 = - 1 add 7 to each side 2n - 7 + 7 = - 1 + 7 2n = 6 divide each sides integer by 2 (2/2)n = 6/2 n = 3 ---------------check in original equation 2(3) - 7 = - 1 6 - 7 = - 1 - 1 = - 1 ----------------checks and equation is satisfied
Suppose N stands for any number. Then 2N will always be even, so 2N + 1 will always be odd. Now let K stand for any other number. Then 2K + 1 will be another odd number. Now suppose we add these two odd numbers ; 2N + 1 + 2K + 1 = 2N + 2K +2 Factor out a 2, 2(K + N + 1) So the result of adding two odd numbers always gives a number which has the factor 2. So it is always an even number. Now add an even number 2N with an odd number 2K + 1 to get; 2N + 2K +1 . Since 2N + 2K is always an even number (has the factor 2 ) then 2N + 2K + 1 will always be an odd number.
n + (n + 1) = 507 2n + 1 = 507 2n = 506 n = 253 therefore 253 and 254 are consecutive numbers that add to 507.
No. of subsets = 2n - 1 3 = 2n - 1 3 + 1 = 2n - 1 + 1 4 = 2n 4/2 = 2n/2 2/1 = 1n/1 2 = n n = 2elements
2n-1 to the tenth term = 1
2n-butoxy1ethanol = 1
1
(2n + 1) + (2n + 3) + (2n + 5) = 309 6n + 9 = 309 subtract 9 to both sides 6n = 300 divide by 6 to both sides n = 50 2n + 1 = 2(50) + 1 = 101 Thus, the three consecutive odd numbers which add up to 309 are 101, 103, and 105