5n + 1 = 10 + 2n5n - 2n + 1 - 1 = 10 - 1 + 2n - 2n3n = 93n/3 = 9/3n = 3
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1
aneuploidy
n = 1
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
That factors to (2n + 1)(n + 2)
Any even number can be written in the form 2n for some natural number n.Any odd number can be written as 2n+1 for a natural number nNow add an even to an odd.2n+2n+1=4n+1 which is 2(2n)+1 and this is the form for an odd number.
5n + 1 = 10 + 2n5n - 2n + 1 - 1 = 10 - 1 + 2n - 2n3n = 93n/3 = 9/3n = 3
(4n + 1)*(2n + 6) = 8n2 + 26n + 6
If: 2n = 1 Then: n = 1/2 or 0.5
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1
aneuploidy
1 + 2 + 4 + ... + 2n = 2n+1 - 1
2n + 1 = 22 Take 1 from the left side of the equal side and move it to the right side. To do this subtract 1 from the left side and on the right side 2n + 1 - 1 = 22 -1 2n = 21 Then divide both sides by 2 in order to isolate n. 2n / 2 = 21 /2 n = 21/2 or 10.5 Tada! The answer is 21/2 or 10.5.
1
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)