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I will assume that we are taking d/dx, not d/dn. There are two ways to interpret what you asked. First way is (sinx)^(2n). Second way is sin(x^(2n)).

First answer: 2n(sinx)^(2n-1)(cosx)=2ncosx(sinx)^(2n-1).

Second answer: cos(x^(2n))(2nx^(2n-1)).

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Q: How do you integrate sin x to the power of 2n?
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