(2x + 3)(x + 1 ) = 2x^2 +5x +3
(2x + 1) (x + 3) = 2x2 + 7x + 3
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
if it is -X then X=5 if it was minus X the X=10
(2x + 3)(x + 1)
(2x + 3)(x + 1 ) = 2x^2 +5x +3
x+3(x+1)=2x x + 3x + 3 = 2x 2x + 3 = 0 2x = -3 or x = -1.5
(2x + 1) (x + 3) = 2x2 + 7x + 3
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
2x + 3 = x + 1 Subtract x from both sides: x + 3 = 1 Subtract 3 from both sides: x = -2
x = 1 ------------- 3 = 2x + 1 -1 -1 2=2x /2 /2 1=x
This equals 3x+3 also written as 3(x+1). If you mean a linear equation like 3x + 3 = 0, then the solution is x = -1
if it is -X then X=5 if it was minus X the X=10
(2x + 3)(x + 1)
4
(x + 3)(x - 1)
1