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Q: What is 3 L W - 8 L L?
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What is the perimeter of a rectangle with a length of 8 in and an area of 24 square inches?

KEY: LENGTH=L WIDTH=W AREA=A If the length of 1 side is 8 and the area is 24, we must find the other length. Since L*W=A we know that L=8 and A=24. So, the problem looks like this: 8*W=24. So, to reverse this, 24 divided by 8 = W. 24 divided by 8 = 3, so we know that L=8 and W=3. Perimeter = W+W+L+L so 8+8+3+3= 22. I hope that you understand the process. Please post something on my page if you need further help.


What is the sides of a rectangle if the perimeter is 16 cm?

The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.


How do you write a polynomial that represents the area of a rectangle with the length is 8 centimeters less than 3 times the width?

Area = L x W. L = 3W - 8 so A = 3W2 - 8W or W(3W - 8)


How do you get 8 as length and 3 as width if you had 24 square tiles and you add all the length and width all togrther and get 11?

Let W = width and L = length. Then we have: L x W = 24 L + W = 11 Then, L = 11 - W, and (11 - W) x W = 24, so 11W - W2 = 24 Rearranging terms: W2 - 11w + 24 = 0 Using the Quadratic Equation with a=1, b=-11 and c=24: W = [11 +/- sqrt((-11)2 - 4x1x24))] / 2 W = [11 +/- sqrt(121-96)] / 2 W = [11 +/- sqrt(25)] / 2 W = [11 +/- 5] / 2 W = 16/2 or 6/2 W = 8 or 3, and L = 3 or 8.


How to draw a rectangle with an area of 12 square centimeters with a perimeter of 16 centimeters?

Suppose length = L and width = Wthen perimeter, P = 2(L + W) = 16 => L + W = 8 and so W = 8 - LAlso, area A = L*W = 12therefore L*(8 - L) = 12 or L^2 - 8L + 12 = 0 => L = 2 or L = 6These are conjugate solutions so (L, W) = (6, 2) centimetres.


The perimeter of an rectangle is 64cm the length is 8cm more than twice the width Find the dimensions?

That means that 2(L+W)=64 => L+W =32. We can also form the equation L = 8+2w. Plugging this expression into the first equation for L we get 8+2w+W = 32. Simplifying we get 3w+8 = 32 => 3w=24 => w=8. Using the fact that L+W=32 and our value for w we get L+8=32 => L=24. Therefore the dimensions are a length of 24cm and a width of 8cm.


Is it length by width or width by length?

There is no difference between L x W and W x L For example if L = 5 and W = 3 L x W -> 5 x 3 = 15 W x L -> 3 x 5 = 15


How do you figure out games ahead of next team?

Find the difference between the two teams' win and losses, divide by two. Example: Team A..........W-10 L-3 Team B..........W- 8 L-5 Team B is 2 games behind Team A Team A..........W-10 L-3 Team B..........W- 8 L-4 Team B is 1 1/2 games behind Team A


What is the length of a rectangle whose perimeter is 64cm if the length is 3 times the width?

Let's denote the width of the rectangle as ( w ) and the length as ( 3w ). The perimeter of a rectangle is given by the formula ( P = 2l + 2w ), where ( l ) is the length and ( w ) is the width. Given that the perimeter is 64 cm, we can write the equation ( 64 = 2(3w) + 2w ). Solving this equation, we find that the width is 8 cm and the length is 24 cm.


What is W. H. L. Wallace's birthday?

W. H. L. Wallace was born on January 8, 1821.


When was W. H. L. Wallace born?

W. H. L. Wallace was born on January 8, 1821.


What is Formula to convert SY to LF?

If the width "W" of your area "A" is, say one yard, that is, 3 feet, then you divide the Area "A" by width "W" to equal length, "L" A = W x L or, A/W = L but since A is in square yards, you need to multiply by 3 (3 ft in a yd) to get L in linear feet. Then the formula becomes, 3(A/W) = L in linear feet