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Lorine Boyle

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5y ago

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What is the perimeter of a rectangle with a length of 8 in and an area of 24 square inches?

KEY: LENGTH=L WIDTH=W AREA=A If the length of 1 side is 8 and the area is 24, we must find the other length. Since L*W=A we know that L=8 and A=24. So, the problem looks like this: 8*W=24. So, to reverse this, 24 divided by 8 = W. 24 divided by 8 = 3, so we know that L=8 and W=3. Perimeter = W+W+L+L so 8+8+3+3= 22. I hope that you understand the process. Please post something on my page if you need further help.


What is the sides of a rectangle if the perimeter is 16 cm?

The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.


How do you write a polynomial that represents the area of a rectangle with the length is 8 centimeters less than 3 times the width?

Area = L x W. L = 3W - 8 so A = 3W2 - 8W or W(3W - 8)


How do you get 8 as length and 3 as width if you had 24 square tiles and you add all the length and width all togrther and get 11?

Let W = width and L = length. Then we have: L x W = 24 L + W = 11 Then, L = 11 - W, and (11 - W) x W = 24, so 11W - W2 = 24 Rearranging terms: W2 - 11w + 24 = 0 Using the Quadratic Equation with a=1, b=-11 and c=24: W = [11 +/- sqrt((-11)2 - 4x1x24))] / 2 W = [11 +/- sqrt(121-96)] / 2 W = [11 +/- sqrt(25)] / 2 W = [11 +/- 5] / 2 W = 16/2 or 6/2 W = 8 or 3, and L = 3 or 8.


How do you draw a rectangle with a perimeter of 12 units and an area equalling 8?

P = 12 = 2( l + w) A = 8 = l*w. Hence 6 = l + w 8 = l X w It follows w = 6 - l Substitute 8 = l X ( 6 - l Myltiply out 8 = 6l - l^(2) l^(2) - 6l + 8 = 0 It is now in Quadratic form ; Factor (l -4)( l -2) = 0 Hence ;(length) = 4 Widt = 2 .


How to draw a rectangle with an area of 12 square centimeters with a perimeter of 16 centimeters?

Suppose length = L and width = Wthen perimeter, P = 2(L + W) = 16 => L + W = 8 and so W = 8 - LAlso, area A = L*W = 12therefore L*(8 - L) = 12 or L^2 - 8L + 12 = 0 => L = 2 or L = 6These are conjugate solutions so (L, W) = (6, 2) centimetres.


The perimeter of an rectangle is 64cm the length is 8cm more than twice the width Find the dimensions?

That means that 2(L+W)=64 => L+W =32. We can also form the equation L = 8+2w. Plugging this expression into the first equation for L we get 8+2w+W = 32. Simplifying we get 3w+8 = 32 => 3w=24 => w=8. Using the fact that L+W=32 and our value for w we get L+8=32 => L=24. Therefore the dimensions are a length of 24cm and a width of 8cm.


How do you figure out games ahead of next team?

Find the difference between the two teams' win and losses, divide by two. Example: Team A..........W-10 L-3 Team B..........W- 8 L-5 Team B is 2 games behind Team A Team A..........W-10 L-3 Team B..........W- 8 L-4 Team B is 1 1/2 games behind Team A


Is it length by width or width by length?

There is no difference between L x W and W x L For example if L = 5 and W = 3 L x W -> 5 x 3 = 15 W x L -> 3 x 5 = 15


The length of a rectangle is 3 times the width and the perimeter is 22 Find the dimensions of the rectangle?

The width is 22/8 or 11/4 or 2.75. The length is 66/8 or 33/4 or 8.25. Length = 3W 3W + 3W + W + W = 8W 8W = 22 W = 22/8 L = 66/8 Then, you can simplify as you choose.


What is the length of a rectangle whose perimeter is 64cm if the length is 3 times the width?

Let's denote the width of the rectangle as ( w ) and the length as ( 3w ). The perimeter of a rectangle is given by the formula ( P = 2l + 2w ), where ( l ) is the length and ( w ) is the width. Given that the perimeter is 64 cm, we can write the equation ( 64 = 2(3w) + 2w ). Solving this equation, we find that the width is 8 cm and the length is 24 cm.


What is W. H. L. Wallace's birthday?

W. H. L. Wallace was born on January 8, 1821.