9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
We have 3x+9y=36, or equivalently 12x+36y=144. We also have 12x+4y=18, so subtracting these we have 32y=126 or y=63/16. Substituting this into our original equation leaves 3x=36-9*63/16 or x = 12-3*63/16 = 3/16. So: x=3/16, y=63/16
(3x - 7)(2x + 9) = 0 x = 7/3 or -9/2
63 +99 ___ 162
3 / 9x+63 / 3(3x+2)1 / 3x+2
9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
y=3x+7 7x +3y=63
We have 3x+9y=36, or equivalently 12x+36y=144. We also have 12x+4y=18, so subtracting these we have 32y=126 or y=63/16. Substituting this into our original equation leaves 3x=36-9*63/16 or x = 12-3*63/16 = 3/16. So: x=3/16, y=63/16
(3x - 7)(2x + 9) = 0 x = 7/3 or -9/2
lets call the one number X and the other Y so y equals 3X so 3X plus X equals 84 so 4X equals 84 we divide by 4 so x equals 21 so y equals 21 times 3 equals 63 so the two numbers are 63 and 21
63 +99 ___ 162
63+59+75 = 197
'63'
3 / 9x+63 / 3(3x+2)1 / 3x+2
The answer is the number for 'y' that makes the equation a true statement.Here's how to find it:63 - y = 2y + 3Add 'y' to each side:63 = 3y + 3Subtract 3 from each side:60 = 3yDivide each side by 3:20 = y
63 plus 47 plus 42 plus 21 is equal to 173.
the number = -20Let = the number3 times a number = 3 * x or 3xdifference of 9 and 3 times a number = 9 - 3xdifference of 9 and three times a number equals 69: 9 - 3x = 699 - 3x = 699 - 3x - 9 = 69 - 9-3x = 60-3x/-3 = 60/-3x = -20