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If n multiplied by 0 equals 0 than that must mean 0 divided by 0 equals n so 0 divided 0 is every number correct?
Answer: you can not divide 0 with its self or any other number. Answer: Since ANY number times 0 = 0, the inverse operation is not defined. It is know that that allowing a division by zero - even if it is 0 / 0 - leads to all kinds of errors. Answer: While your logic is well founded...under your logic 0 divided by 0 does indeed equal n but that does not mean that 0 divided by 0 equals every number...in fact n is an undefined variable that means absolutely nothing (even though you are trying to define it as every number) and math tells us that anything divided by zero (including 0 itself) does not exist or cannot be defined
What are the first 3 terms of n-2 divided by n squared?
5
Which number between 1 and 100 satisfies the following conditions . when divided by 3 or 5 the remainder is 1. when divided by 7 there is n remainder 0?
How about 91
0 divided by 7 what is the answer?
0
What is 2 to zero power?
1. All numbers to the zero power are 1. Take any number a^n we know that a^n/a^n=1 since anything divided by itself is 1. We also know the rule for division tells us a^n/a^n= a^(n-n)=a^0. so it is 1. 0^0 is usually defined as 1, but in some context people say it is indeterminate.
Can 0 be evenly divided by 4?
0
N C be D to 0?
nothing can be divided to 0
Why does n divided by 0 equals 0?
its not zero. Its Infinitive.
N C be D to O?
Nothing can be Divided to 0
If n multiplied by 0 equals 0 than that must mean 0 divided by 0 equals n so 0 divided 0 is every number correct?
Answer: you can not divide 0 with its self or any other number. Answer: Since ANY number times 0 = 0, the inverse operation is not defined. It is know that that allowing a division by zero - even if it is 0 / 0 - leads to all kinds of errors. Answer: While your logic is well founded...under your logic 0 divided by 0 does indeed equal n but that does not mean that 0 divided by 0 equals every number...in fact n is an undefined variable that means absolutely nothing (even though you are trying to define it as every number) and math tells us that anything divided by zero (including 0 itself) does not exist or cannot be defined
What property states that a number divided by itself is equal to 1?
Properties of Division: n/n =1, If n ≠ 0. Any number other than zero divided by itself is one.
What are the first 3 terms of n-2 divided by n squared?
5
What is power to zero?
1. All numbers to the zero power are 1. Take any number a^n we know that a^n/a^n=1 since anything divided by itself is 1. We also know the rule for division tells us a^n/a^n= a^(n-n)=a^0. so it is 1. 0^0 is usually defined as 1, but in some context people say it is indeterminate.
Which is true 15 divided by 0 equals 0 or 0 divided by 15 equals 0?
0 divided by15 = 0 15 divided by 0 is undetermined ( infinite)
Which number between 1 and 100 satisfies the following conditions . when divided by 3 or 5 the remainder is 1. when divided by 7 there is n remainder 0?
How about 91
Why does any number to the zero power equal one?
Here is why any number to the zero power equals one. Consider this. a^b. it is natural to restrict a > 0, but we'll only assume that number b is any real number. We'll use the natural exponential function defined by the derivative of the exponential function. Now we have a^r=e^rln(a). And we know that e^rln(a)=e^((ln(a))^r), where a >0 and r is in the domain of all real numbers negative infinity to infinity. We can apply this definition to any number a to any power r. Particularly, a^0. By the provided definition, a^0=e^(0*ln(a))=e^0=1. Furthermore, a^1=e^(1*ln(a))=e(ln(a))=a. And a^2=(e^(ln(a))^2)=a^2. ---------------------------------- Here is a simpler approach: In general, a^n/a^m = a^(n-m) and a/a = 1. We can use these facts to prove that x^0 = 1 so long as x isn't 0. First, state the obvious: 1 = 1 Next, since any non-zero number divided by itself is one: 1 = a^n/a^n (It doesn't change how the equation looks, but for the sake of being thorough, you could subsitute (a^n/a^n) in place of 1 in the original equation.) Then, since dividing like bases requires that you subtract their exponents: a^n/a^n = a^(n-n) = a^0 Substitute (a^0) in for (a^n/a^n) and you obtain: a^0 = 1 There are two reasons "a" cannot be 0 in this proof: firstly, raising 0 to non-zero powers would still result in zero, so "a" being 0 would cause division by zero in the initial theorems we used, and secondly, 0^0 is considered undefined in itself.
When you add a number that has a remainder of 1 when it is divided by 3 to a number that has a remainder of 2 when it is divided by 3 then what is the remainder of the sum when you divide it by 3?
The remainder is 0.If A has a remainder of 1 when divided by 3, then A = 3m + 1 for some integer mIf B has a remainder of 2 when divided by 3, then B = 3n + 1 for some integer n→ A + B = (3m + 1) + (3n + 2)= 3m + 3n + 1 + 2= 3m + 3n + 3= 3(m + n + 1)= 3k where k = m + n + 1 and is an integer→ A + B = 3k + 0→ remainder when A + B divided by 3 is 0-------------------------------------------------------------------------From this, you may be able to see that:if A when divided by C has remainder Ra; andif B when divided by C has remainder Rb; then(A + B) divided by C will have remainder equal to the remainder of (Ra + Rb) divided by C
