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The first three terms of (n-2)/n2 are -1, 0 and 1/9.
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5*n2
tn = n2 - 3 Thus: t1 = 12 - 3 = 1 - 3 = -2 t2 = 22 - 3 = 4 - 3 = 1 t3 = 32 - 3 = 9 - 3 = 6 t4 = 44 - 3 = 16 - 3 = 13 So the first four terms of n2 -3 are -2, 1, 6 & 13.
(m2n2)2 = m4n4
n x n2 = n3