A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
If the original slope is 0, then the opposite reciprocal of 0 is still 0. Oops! Reciprocal of 0 (n/0) is undefined! A vertical line has undefined slope, the horizontal line has slope of 0.
The slope is undefined.
No slope is undefined i.e. a vertical line slope of 0 is a horizontal line... i believe...
Points: (-1, -1) and (0, 0) Slope: 1
y=mx has a slope of m, if the slope is 0, m must be 0. So the coefficient of x is 0.
Slope = 0
No, they are perpendicular.
Slope = (8 - 0)/(0 - 4) = -2
if the slope is 0, the line is horizontal.
Points: (0, 6) and (6,0) and the slope of the line works out as -1
Because V in is the slope and when A is 0 slope is not 0 so v cant be 0
Points: (0, 0) and (2, 6) Slope: 3
The answer is 0.
The slope is zero.
The slope of a vertical line is undefined. Horizontal slope is 0.
Horizontal lines have a slope of 0.
this would be a slope of 5
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
Points: (0, 0) and (4, 1) Slope: 1/4
If you mean: (0, 0) and (6, 7) then the slope works out as 7/6
The slope of the line joining (0,3) and (3,0) is -1