What value would you like?
U{n} = (5x⁵ - 75x⁴ + 425x³ - 1125x² + 1394x - 336)/24
U{1} = 12
U{2} = 13
U{3} = 14
U{4} = 15
U{5} = 16
U{6} = 42
U{50} = 47,672,161
However, I suspect your teacher wants the much simpler sequence U{n} = n + 11
→ U{50} = 50 + 11 = 61
------------------------------
This shows the problem with extrapolating data beyond given data - there are infinitely many polynomials which will give the sequence so far but will diverge for values outside the given range.
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid.
For example, using the function Un = (-7*x5 + 105*x4 - 595*x3 + 1575*x22 - 1798*x + 2160)/120, the
50th term would be -13348127. For ANY other value, you simply need to select the appropriate polynomial.
If you select the simplest rule, Un+1 = Un + 11 then the answer is 61.
55,73and 110
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
3
The 'n'th term is [ 13 + 5n ].
It is -173
55,73and 110
-13
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
The answer is 15 because the pattern is subtract one, add two
-47
4 5 6 7 8 9 10 11 12 13
To find the nth term of a sequence, we first need to determine the pattern or rule that governs the sequence. In this case, the sequence appears to be increasing by adding consecutive odd numbers: 3, 6, 9, 12, and so on. Therefore, the nth term formula for this sequence is Tn = 3n^2 + n. So, the nth term for the sequence 4, 7, 13, 22, 34 is Tn = 3n^2 + n.
PRIME
3
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].