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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc.
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Y1=2x^(2/3)+√(20-x²)-3 Y2=2x^(2/3)-√(20-x²)-3
Here it is: Y1=2x^(2/3)+√(20-x²)-3 Y2=2x^(2/3)-√(20-x²)-3
Definition of the inverse of a function.Let f and g be two functions such thatf(g(x)) = x for every x in the domain of g andg(f(x)) = x for every x in the domain of f.The function g is the inverse of the function f, and the domain of f is equal to the range of g, and vice versa.Example: Find the inverse of y1 = 2x + 7Solutiony1 = 2x + 7 interchange x and y;x = 2y1 + 7 solve for y;x - 7 = 2y1 + 7 -7 subtract 7 to both sides;x - 7 = 2y1 divide by 2 both sides;(x - 7)/2 = y1 replace y1 with y2;y2 = (x - 7)/2Thus, the inverse of y1 = 2x +7 is y2 = (x -7)/2Let's check if this is true according to the above definition:Let y1 = f(x) = 2x +7 and y2 = g(x) = (x -7)/21. f(g(x))= x ?f(x) = 2x + 7f((x - 7)/2) = 2[(x -7)/2] + 7 = x - 7 + 7 = x True2. g(f(x) = x ?g(x) = (x - 7)/2g(2x + 7) = [(2x + 7) - 7]/2 = 2x/2 = x True
Use the point-slope form: y - y1 = m(x - x1). From the givens, y1 = 2, x1 = 9, and m = -2. Thus, y - 2 = -2(x - 9) = -2x + 18, or y = -2x + 20.
(-1,3),(5,-9) (y2-y1)/(x2-x1)= (-9-3)/(5--1)= (-12/6)= the slope is -2 m(x-x1)=y-y1 -2(x-5)=y--9 -2x+10=y+9 y=-2x+1
y-y1=m(x-x1) y-7=2(x-3) y-7=2x-6 y=2x-1 y=2x-1
Use the slope intercept form here, Y - Y1 = m(X - X1) m = 2 Y1 and X1 = (3, 7) (Y - 7) = 2(X - 3) Y - 7 = 2X - 6 Y = 2X + 1 ----------------the equation of the line
There are many calculations that could be done: =SUM(Y1:Y10) =AVERAGE(Y1:Y10) =MAX(Y1:Y10) =MIN(Y1:Y10) =COUNT(Y1:Y10)
5x-y1 = 4
Without an equality sign the given terms of an expression can't be considered to be an equation and so therefore no solution is possible.
To find the line that passes through the points (3, -5) and (2, -3), you can plug those numbers into the classic equation for a line: Δy = sΔx or: (y - y1) = s(x - x1) You can calculate the slope given the numbers that are already provided: s = Δy/Δx s = ((-5) - (-3)) / (3 - 2) s = (3 - 5) / (3 - 2) s = -2/1 s = -2 Now that you have the slope, you can use it in the original line equation, plugging either of the two points in to your x1 and y1 values: (y - y1) = s(x - x1) y - (-5) = -2(x - 3) y + 5 = -2x + 6 y = 1 - 2x You could also plug in the other pair of x/y values to get the same result: (y - y1) = s(x - x1) y - (-3) = -2(x - 2) y + 3 = -2x + 4 y = 1 - 2x
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