(-1,3),(5,-9)
(y2-y1)/(x2-x1)= (-9-3)/(5--1)= (-12/6)= the slope is -2
m(x-x1)=y-y1
-2(x-5)=y--9
-2x+10=y+9
y=-2x+1
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
the slope is 1, and goes through the origin. It's a straight, diagonal line.
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
The line goes through two numbers, so it can only be the 1-dimensional number line.
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean: y = 2x-4 and (1, 5) then the parallel equation is y = 2x+3
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
The answer is: y = 1/2x + 4
the slope is 1, and goes through the origin. It's a straight, diagonal line.
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
If you mean: y = 3x-3 and (-2, 1) then it is y = 3x+7
The equation of a line through (-1,7) and (-4,9) is y=-(2/3)*x+19/3
From the information given it appears to have no slope if x0 and so there is no equation as such but plotted on a grid there will be a straight vertical line and a straight horizontal line that meet each other at right angles.