2.5
If the sum of the digits in a two-digit number is 15, and the number is 6 more than 15 times the units digit, the number is 96. Let A and B be the digits. (A is the tens digit and B is the units digit) A + B = 15, therefore A = 15 - B 10A + B = 15B + 6Substituting for A, and solving for B...10(15 - B) + B = 15B + 6150 - 10B + B = 15B + 6150 - 9B = 15B + 6144 - 9B = 15B144 = 24BB = 6 Back substitute B into first equation and solve for A...A + 6 = 15A = 9 Therefore, the digits are 9 and 6, so the number is 96.
140625
Mean = sum of all numbers divided by number of numbers you summed. Call numbers a, b, c, d, e, f (a+b+c+d+e+f)/6 = mean
B/5 = 6 means that 6 x 5 = B 6 x 5 = 30 Therefore, B = 30
15 and 3--a + b = 18a = 18 - ba * b = 45(1-b)*b = 4518b-b^2 = 45b^2-18b = -45b^2-18b+81 = 36(b-9)^2 = 6^2b-9 = +/-6b = 9+/-6 = 3, 15a = (18 -b ) = 18 - 9 +/- 6a = 15, 3
2.5
2.5
2.5
2.5
If the sum of the digits in a two-digit number is 15, and the number is 6 more than 15 times the units digit, the number is 96. Let A and B be the digits. (A is the tens digit and B is the units digit) A + B = 15, therefore A = 15 - B 10A + B = 15B + 6Substituting for A, and solving for B...10(15 - B) + B = 15B + 6150 - 10B + B = 15B + 6150 - 9B = 15B + 6144 - 9B = 15B144 = 24BB = 6 Back substitute B into first equation and solve for A...A + 6 = 15A = 9 Therefore, the digits are 9 and 6, so the number is 96.
(a+b)/6
(a + b)/(xy)
140625
Mean = sum of all numbers divided by number of numbers you summed. Call numbers a, b, c, d, e, f (a+b+c+d+e+f)/6 = mean
if you let b= amount of money then b/20 = 7
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
You add 2 fractions with the same denominator [c], so the sum is the sum of the numerators divided by the denominator: a/c + b/c = (a+b)/c