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There are 286 possible sets of three, (any 3 from 13). There are 28 pairs of reds and 5 possible greens so probability is 5 x 28 ie 140 out of 286 which is just under half (0.4895).
1 in 5.45 of picking at least 2 blue marbles any 2 from 3 is 3 correct picks =3X7(red)=21 of 2 blue only 1 pick of 3 blue only any 3 from 10=120 120/22=5.45
The probability is 100%.There's no way to take four marbles out of this bag without at least one of them being white.
The second and third marbles depend upon the first, so they are dependent. Even if they are all being drawn together, because there is no replacement, each removal affects the original group of marbles.
It is (1/2)5 = 1/32